php中输出json对象的值(实现方法)

网络编程 2024/9/25 佚名

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实例如下所示：

 <!DOCTYPE html>
<html>
<body>
<"report":{"date":"2012-04-10","content":"abcdefght"}}';
 $arr = (array) json_decode($json,true);
 echo '当前日期是：'. $arr['report']['date'];
echo "<br/>";
echo '<pre>';
 print_r($arr);
echo '</pre>'; 
 
 foreach($arr as $arrvalue)
 {
 foreach($arrvalue as $key=>$value)
 {
  echo "[$key] = $value <br />";
 }
 }
echo "<br/>";
"text-align: center">


<!DOCTYPE html>
<html>
<body>
<"json.txt");
if( $file_exists ){
 $myfile = fopen("json.txt", "r") or die("");
 $content = fread($myfile,filesize("json.txt"));
 fclose($myfile);
 echo $content;
 echo "<br/>";
 $arr=(array)json_decode($content,true);
 echo $arr['CSS'];
 echo "<br/>";
 echo $arr['AJAX'];
}
"text-align: center">
json.txt:


{
 "AJAX": "Asynchronous JavaScript and XML",
 "CSS": "Cascading Style Sheets"
}


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